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#include <stdio.h>
#include <stdlib.h>
#include <iostream>

using namespace std;

int main(){

	int b; int b1;

	int N = 5 , D= 7, g =2;

	b = N/D;

	int N1;

	int D1;


	N1 = (N*g);

	D1 = (D*1);

	b1 = b+g;







}

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#include <stdio.h>
#include <stdlib.h>
#include <iostream>

using namespace std;

int main(){

	int N = 5 , D= 7, g =2;

	int N1;
	int D1;

	N1 = N+g*D;
	D1 = D;

	cout << N << "/" << D << " + " << g << " = " << N1 << "/"  << D1 << endl;
}

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int b; int b1;
int N = 5 , D= 7, g =2;
b = N/D;

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double b = N;
b = b/D;

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double b;
b = (0.0+N) / D

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double b;
b = (double)N / D

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if (Zaehler >= Nenner)
    printf("unechter Bruch");
else
    printf("echter Bruch");

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if (Zaehler >= Nenner)
    printf("un");
printf("echter Bruch");

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int rest = a % b;
if (rest == a)  //a ist von dir sinnvoll zu ersetzen, was muss der Rest sein?
    printf("a ist Vielfaches von b");
else
    printf("a ist kein Vielfaches von b");

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a=7; b=3;
rest = a % b; //rest = 7 % 3 = 1
if(rest == 1) //ist ja erfüllt
    printf("a ist Vielfaches von b");

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if(rest == 0)
    printf("%d ist Vielfaches von %d", a, b);

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x += laenge * cos(Pi * winkelInGrad/ 180);