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def A002326(n): # entspricht (PARI) for(i=0, 200, i++; m=0; for(x=1, i, if(((2^x-1))%i==0, m=x; break)); 
	m = 0
	for x in range(1, 2*n+1):
		if (2^x-1) % (2*n+1) == 0:
			return x
	return m

def A002326_(n):
    n = n
    a=1
    m=0
    while True:
        a*=2
        a%=(2*n+1)
        m+=1
        if a==1: break
    return m

for i in range(1,10): print A002326_(i)